A) 1.17 m
B) 1.71m
C) 0.117m
D) 0.171m
Correct Answer: C
Solution :
Here, \[F=9\times 109\frac{{{(1.6\times {{10}^{-19}})}^{2}}}{{{r}^{2}}}\] But \[F=mg=(1.7\times {{10}^{-27}})\times 9.8\] \[\therefore \]\[(1.7\times {{10}^{-27}})\times (9.8)=9\times {{10}^{9}}\frac{{{(1.6\times {{10}^{-19}})}^{2}}}{{{r}^{2}}}\] Solving, we get \[r=0.117\,\,metre\]You need to login to perform this action.
You will be redirected in
3 sec