A) 10.27 ohms
B) 12.27 ohms
C) 8.62 ohms
D) 16.24 ohms
Correct Answer: A
Solution :
\[V=iR\] \[220-36=15R\] \[\Rightarrow \] \[R=\frac{184}{15}\] \[=12.27\Omega \] \[\therefore \] \[{{R}_{1}}=12.27-2\] \[=10.27\Omega \]You need to login to perform this action.
You will be redirected in
3 sec