A) 64 W
B) 80 W
C) 100 W
D) 125 W
Correct Answer: A
Solution :
\[P\propto {{V}^{2}}\] So, \[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{{{V}_{2}}}{{{V}_{1}}} \right)}^{2}}\] or \[{{P}_{2}}=100{{\left( \frac{16}{20} \right)}^{2}}=100\times \frac{16}{25}=64\]You need to login to perform this action.
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