A) \[{{r}_{1}}+{{r}_{2}}\]
B) \[{{r}_{1}}-{{r}_{2}}\]
C) \[{{r}_{2}}-{{r}_{1}}\]
D) \[{{r}_{1}}{{r}_{2}}\]
Correct Answer: B
Solution :
The drop across the internal resistance of first cell \[{{r}_{1}}\] is\[E\]. So, the total drop across \[{{r}_{2}}\] and must also be\[E\] \[I{{r}_{1}}=I({{r}_{2}}+R)\](in series,\[I\]is same) \[\therefore \] \[R={{r}_{1}}-{{r}_{2}}\]You need to login to perform this action.
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