A) copper at anode and sulphate at cathode
B) sulphur at anode and copper at cathode
C) oxygen at anode and copper at cathode
D) copper at anode and oxygen at cathode
Correct Answer: C
Solution :
Platinum electrodes are non-attackable. So, the disulphate ion at the anode cannot react with it. \[O{{H}^{-}}\] ion in the acqueous medium liberation\[{{O}_{2}}\]. \[S{{O}_{4}}^{--}\]reacts with\[{{H}^{+}}\]to form\[{{H}_{2}}S{{O}_{4}}\].You need to login to perform this action.
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