A) 9 sec
B) 9 min
C) 900 sec
D) 900 min
Correct Answer: C
Solution :
Mass of copper deposited\[=\]Volume \[\times \] Density \[=10\times 1.65\times \frac{0.1}{10}\times 9\] Time taken for deposition, \[t=\frac{m}{zi}=\frac{10\times 1.65\times 0.1\times 9}{10\times 0.0033\times 10}\sec \] \[=\,\,\mathbf{450}\] sec. Since, above is the time for copper deposition on one side, therefore time taken for both sides \[=2\times 450=\mathbf{900sec}\].You need to login to perform this action.
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