A) 10
B) 100
C) 600
D) 60
Correct Answer: B
Solution :
\[{{I}_{g}}=I\cdot \frac{S}{S+G}\] \[\therefore \] \[1=100\times \frac{S}{S+600}\] \[\Rightarrow \] \[S=\frac{600}{99}\] or \[M.F.=\frac{S+G}{S}=\frac{\frac{600}{99}+600}{\frac{600}{99}}=100\Omega \]You need to login to perform this action.
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