A) PQ
B) QR
C) PS
D) RS
Correct Answer: B
Solution :
When the \[100\Omega \] resistor is connected in parallel to\[QR\], its resistance becomes\[\frac{200}{3}\Omega \]. Now the ratio\[QC\], becomes equal to\[\frac{QR}{SR}\].You need to login to perform this action.
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