A) 6 series
B) 8 series
C) 6 parallel
D) 8 parallel
Correct Answer: C
Solution :
\[{{R}_{E}}=\frac{V}{I}=\frac{50}{2}=25\Omega \frac{1}{25}=n\left( \frac{1}{150} \right),\] where 'n' is the number of resistors. \[\therefore \] \[n=150/25=6\] 6 resistors of \[25\Omega \]. must be connected in parallel since, \[{{R}_{E}}\] must be lower than \[150\,\Omega \].You need to login to perform this action.
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