A) + 1.36 V
B) + 2.71 V
C) + 2.17 V
D) ? 3.01 V
Correct Answer: B
Solution :
\[E_{Cu}^{0}>E_{Mg}^{0}\]hence Cu acts as cathode and Mg acts as anode. \[E_{Cell}^{0}=E_{Cu}^{0}-E_{Mg}^{0}\] \[=(0.34)-(-2.37)=+2.71\ V\].You need to login to perform this action.
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