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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Electrode potential Ecell Nernst equation and ECS

  • question_answer
    For the electrochemical cell, \[M|{{M}^{+}}||{{X}^{-}}|X,\] \[E{}^\circ ({{M}^{+}}|M)\]\[=0.44\ V\]\[E{}^\circ (X|{{X}^{-}})=0.33\ V\]From this data, one can deduce that                                         [Pb.CET 2004]

    A)                 \[E{{{}^\circ }_{cell}}=-0.77\,V\]

    B)                 \[{{M}^{+}}+{{X}^{-}}\to M+X\] is the spontaneous reaction

    C)                 \[M+X\to {{M}^{+}}+{{X}^{-}}\]is the spontaneous reaction

    D)                 \[E{{{}^\circ }_{cell}}=.77\ V\]

    Correct Answer: B

    Solution :

               For \[{{M}^{+}}+{{X}^{-}}\to M+X\]                    \[E_{Cell}^{0}=E_{Cathode}^{0}+E_{Anode}^{0}\]\[=0.44-0.33=+0.11\ V\]                                 Since \[E_{Cell}^{0}=(+)\ 0.11\ V\] is positive hence this reaction should be spontaneous.


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