A) \[{{E}_{{{M}^{n+}}/M}}={{E}^{o}}_{{{M}^{n+}}/M}+\frac{0.0591}{n}\log \,({{M}^{n+}})\]
B) \[{{E}_{{{M}^{n+}}/M}}={{E}^{o}}_{{{M}^{n+}}/M}-\frac{0.0591}{n}\log \,({{M}^{n+}})\]
C) \[{{E}_{{{M}^{n+}}/M}}={{E}^{o}}_{{{M}^{n+}}/M}+\frac{n}{0.0591}\log \,({{M}^{n+}})\]
D) None of the above
Correct Answer: A
Solution :
\[E={{E}^{o}}-\frac{RT}{nF}\ln \frac{1}{[{{M}^{n+}}]}\];\[E={{E}^{o}}+\frac{RT}{nF}\ln [{{M}^{n+}}]\] \[E={{E}^{o}}+\frac{2.303RT}{nF}\log [{{M}^{n+}}]\] Substituting the value of R, T (298K) and F we get \[E={{E}^{o}}+\frac{0.0591}{n}\log ({{M}^{n+}})\].
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