A) \[{{10}^{-28}}\]
B) \[{{10}^{-37}}\]
C) \[{{10}^{+18}}\]
D) \[{{10}^{+17}}\]
Correct Answer: B
Solution :
\[E_{cell}^{o}=\frac{0.059}{n}\log \,\,K\] \[\log \,\,K=\frac{1.10\times 2}{0.059}=37.2881\] or \[K={{10}^{-37}}\].You need to login to perform this action.
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