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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Electrode potential Ecell Nernst equation and ECS

  • question_answer
    For the cell reaction, \[2C{{e}^{4+}}+Co\to 2C{{e}^{3+}}+C{{o}^{2+}}\] \[E{{{}^\circ }_{cell}}\]is 1.89 V. If \[E{{{}^\circ }_{C{{e}^{4+}}/C{{e}^{3+}}}}\]                   [Pb.CET 2000]

    A)                 ? 1.64 V               

    B)                 + 1.64 V

    C)                 ? 2.08 V               

    D)                 + 2.17 V

    Correct Answer: B

    Solution :

               In this cell Co is oxidised and it acts as anode and Ce acts as cathode.                    \[E_{Cell}^{0}=E_{Cathode}^{0}-E_{Anode}^{0}\] \[=1.89=E_{Cell}^{0}-(-0.28)\]                                 \[E_{Cell}^{0}=1.89-0.28=1.61\]Volts.


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