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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Electrode potential Ecell Nernst equation and ECS

  • question_answer
    Consider the following \[{{E}^{0}}\]values :                 \[{{E}^{0}}_{F{{e}^{3+}}/F{{e}^{2+}}}\] =\[+0.77\ V\]                 \[{{E}^{0}}_{S{{n}^{2+}}/Sn}=-0.14\ V\]                    Under standard conditions the potential for the reaction \[S{{n}_{(s)}}+2F{{e}^{3+}}(aq)\to 2F{{e}^{2+}}(sq)+S{{n}^{2+}}(aq)\] is      [AIEEE 2004]

    A)                 0.91 V   

    B)                 1.40 V

    C)                 1.68 V   

    D)                 0.63 V

    Correct Answer: A

    Solution :

               For \[S{{n}_{(s)}}+2Fe_{(aq)}^{3+}\to 2Fe_{(aq)}^{2+}+Sn_{(aq)}^{2+}\]                    \[E_{Cell}^{0}=E_{Sn/S{{n}^{2+}}}^{0}+E_{F{{e}^{3+}}/F{{e}^{2+}}}^{0}\] \[=(0.14)+(0.77)\]                                 \[E_{Cell}^{{}}=0.91\ Volts\].


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