A) 3.66 V
B) 0.80 V
C) ? 0.80 V
D) ? 3.66 V
Correct Answer: A
Solution :
\[{{E}_{A}}=2.23\,V>{{E}_{B}}=1.43\ V\] So A will act as cathode in galvanic cell. Hence \[E_{Cell}^{0}={{E}_{Cathode}}-{{E}_{Anode}}\]\[={{E}_{A}}-{{E}_{B}}\] \[=(2.23)-(-1.43)\] \[=3.66\ V\].You need to login to perform this action.
You will be redirected in
3 sec