A) ? 1.64 V
B) + 1.64 V
C) ? 2.08 V
D) + 2.17 V
Correct Answer: B
Solution :
In this cell Co is oxidised and it acts as anode and Ce acts as cathode. \[E_{Cell}^{0}=E_{Cathode}^{0}-E_{Anode}^{0}\] \[=1.89=E_{Cell}^{0}-(-0.28)\] \[E_{Cell}^{0}=1.89-0.28=1.61\]Volts.You need to login to perform this action.
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