A) \[+1.66\ V\]
B) \[-3.26\,V\]
C) \[3.26\ V\]
D) \[-1.66\ V\]
Correct Answer: D
Solution :
Al displaces H from HCl but silver cannot it means Al is situated above the Ag in ECS, hence Al will acts as anode and Ag will act as cathode. \[E_{Cell}^{0}=E_{Cathode}^{0}-E_{Anode}^{0}\] \[=E_{A{{g}^{+}}/Ag}^{0}-E_{A{{l}^{3+}}/Al}^{0}\] \[2.46=0.8-E_{A{{l}^{3+}}/Al}^{0}\]; \[E_{Al}^{0}=0.8-2.46=-1.66\ V\].You need to login to perform this action.
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