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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Electrode potential Ecell Nernst equation and ECS

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    \[EMF\]of cell \[Ni\,\,|\,\,N{{i}^{2+}}\,(1.0\,M)\,\,||\,\,A{{u}^{3+}}\,(1.0\,M)\,\,|\,\,Au\] (Where \[{{E}^{o}}\] for \[N{{i}^{2+}}\,\,|\,\,Ni\] is \[-0.25\,\,V;\,\,{{E}^{o}}\] for \[A{{u}^{+3\,}}\,|\,\,Au\] is \[1.50\,\,V)\] is     [MP PET 1993; MP PMT 2000]

    A)                 + 1.25 V               

    B)                 \[-\,1.75\,\,V\]

    C)                 + 1.75 V               

    D)                 + 4.0 V

    Correct Answer: C

    Solution :

                    \[{{E}_{\text{cell}}}=E_{A{{u}^{3+}}/Au}^{o}-E_{N{{i}^{2+}}/Ni}^{o}\]\[=1.50-(-0.25)=1.75\]V.


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