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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Electrode potential Ecell Nernst equation and ECS

  • question_answer
    The standard electrode potential for the two electrode \[{{A}^{+}}/A\] and \[{{B}^{+}}/B\] are respectively 0.5 \[V\] and 0.75 \[V\]. The \[emf\] of the given cell  \[A\,\,|\,\,{{A}^{+}}(a=1)\,\,||\,\,{{B}^{+}}(a=1)\,\,|\,\,B\] will be

    A)                 1.25 \[V\]           

    B)                 ? 1.25 \[V\]

    C)                 ? 0.25 \[V\]        

    D)                 0.25 \[V\]

    Correct Answer: D

    Solution :

       \[\overset{\text{Anode}}{\mathop{A|{{A}^{+}}(a=1)||}}\,\overset{\text{Cathode}}{\mathop{{{B}^{+}}(a=1)\text{ }\!\!|\!\!\text{ }B}}\,\]                       \[EMF={{E}_{cathode}}-{{E}_{anode}}\]\[=0.75-(0.5)\]; \[EMF=0.25\,V\].


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