A) \[Zn\] will reduce \[F{{e}^{2+}}\]
B) \[Zn\] will reduce \[M{{g}^{2+}}\]
C) \[Mg\] oxidises \[Fe\]
D) \[Zn\] oxidises \[Fe\]
Correct Answer: A
Solution :
\[E_{Z{{n}^{++}}/Zn}^{o}<E_{F{{e}^{++}}/Fe}^{o}\], so Zn will reduce \[F{{e}^{++}}\]. \[Zn\] cannot reduce \[M{{g}^{2+}}\] because \[E_{Z{{n}^{++}}/Zn}^{o}>E_{M{{g}^{++}}/Mg}^{o}\] On similar reason Mg and \[Zn\]cannot oxidize \[Fe\].
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