A) 1.10 V
B) 0.42 V
C) ? 1.1V
D) ? 0.42 V
Correct Answer: A
Solution :
\[E_{\text{cell}}^{o}=E_{\text{cathode}}^{o}-E_{\text{anode}}^{o}\]\[=0.34-(-\,0.76)\]\[=1.10\,\,V\].
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