A) 2.14 volt
B) 1.80 volt
C) 1.07 volt
D) 0.82 volt
Correct Answer: C
Solution :
\[E={{E}^{o}}-\frac{0.059}{n}\log \frac{[Z{{n}^{++}}]}{[C{{u}^{++}}]}\]\[=1.10-\frac{0.059}{2}\log \frac{1}{0.1}\] \[=1.10-0.0295\,\log \,10=1.07\,volt\].You need to login to perform this action.
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