A) Ecathode + Eanode
B) Eanode ? Ecathode
C) Ecathode ? Eanode
D) Eleft ? Eright
Correct Answer: C
Solution :
\[E_{\text{cell}}^{o}={{E}_{\text{cathode}}}-{{E}_{\text{anode}}}\].You need to login to perform this action.
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