JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Electrode potential Ecell Nernst equation and ECS

  • question_answer
    Electrode potential data are given below :                 \[F{{e}^{3+}}(aq)+{{e}^{-}}\to F{{e}^{-1}}(aq);\,{{E}^{o}}=+0.77V\]                 \[A{{l}^{3+}}(aq)+3{{e}^{-}}\to Al(s);\,{{E}^{o}}=-1.66V\]                 \[B{{r}_{2}}(aq)+2{{e}^{-}}\to 2B{{r}^{-}}(aq);\,{{E}^{o}}=+1.08\,V\]                 Based on the data given above, reducing power of \[F{{e}^{2+}},\,Al\] and \[B{{r}^{-}}\] will increase in the order                 [Pb. PMT 1998]

    A)                 \[B{{r}^{-}}<F{{e}^{2+}}<Al\]     

    B)                 \[F{{e}^{2+}}<Al<B{{r}^{-}}\]

    C)                 \[Al<B{{r}^{-}}<F{{e}^{2+}}\]     

    D)                 \[Al<F{{e}^{2+}}<B{{r}^{-}}\]

    Correct Answer: A

    Solution :

                    Reducing power, i.e. the tendency to lose electrons increases as the reduction potential decreases.


You need to login to perform this action.
You will be redirected in 3 sec spinner