A) 1.56 V
B) 0.036 V
C) ? 1.562 V
D) 0.799 V
Correct Answer: A
Solution :
\[E_{\text{cell}}^{o}=E_{\text{cathode}}^{o}-E_{\text{anode}}^{o}\]=\[0.799-(-0.763)=1.562\]VYou need to login to perform this action.
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