JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Electrode potential Ecell Nernst equation and ECS

  • question_answer
    A solution containing one mole per litre of each \[Cu{{(N{{O}_{3}})}_{2}},\,\,AgN{{O}_{3}},\,\,H{{g}_{2}}{{(N{{O}_{3}})}_{2}}\] and \[Mg{{(N{{O}_{3}})}_{2}},\] is  being electrolysed by using inert electrodes. The values of standard electrode potentials in volts (reduction potentials) are \[Ag/A{{g}^{+}}=+0.80,\,\,2Hg/Hg_{2}^{2+}=+0.79,\,\,Cu/C{{u}^{2+}}=+0.34,\]\[Mg/M{{g}^{2+}}=-2.37\]with increasing voltage,  the sequence of deposition of metals on the cathode will be [IIT 1984; AMU 1999; Kerala PMT 2004]

    A)                 \[Ag,\,\,Hg,\,\,Cu,\,\,Mg\]         

    B)                 \[Mg,\,\,Cu,\,\,Hg,\,\,Ag\]

    C)                 \[Ag,\,\,Hg,\,\,Cu\]        

    D)                 \[Cu,\,\,Hg,\,\,Ag\]

    Correct Answer: C

    Solution :

                    A cation having highest reduction potential will be reduced first and so on. However, \[M{{g}^{2+}}\] in aqueous solution will not be reduced \[\left( E_{M{{g}^{2+}}/Mg}^{0}<E_{{{H}_{2}}O/\frac{1}{2}{{H}_{2}}+O{{H}^{-}}}^{{}} \right)\]. Instead water would be reduced in preference.


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