question_answer

The e.m.f. of the cell in which the following reaction \[Zn(s)+N{{i}^{2+}}(a=1.0)\]⇌ \[Z{{n}^{2+}}(a=10)+Ni(s)\] occurs, is found to be \[0.5105\,V\] at \[298K\]. The standard e.m.f. of the cell is [Roorkee Qualifying 1998]

A)                 0.5400  

B)                 0.4810 V

C)                 0.5696 V              

D)                 ? 0.5105 V