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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Electrode potential Ecell Nernst equation and ECS

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    The \[{{E}^{o}}\] for half cells \[Fe/F{{e}^{2+}}\] and \[Cu/C{{u}^{2+}}\] are ? 0.44 V and  + 0.32 V respectively. Then                [MP PMT 2003]

    A)                 \[C{{u}^{2+}}\]oxidises \[Fe\]   

    B)                 \[C{{u}^{2+}}\]oxidises \[F{{e}^{2+}}\]

    C)                 \[Cu\] oxidises \[F{{e}^{2+}}\]  

    D)                 \[Cu\] reduces \[F{{e}^{2+}}\]

    Correct Answer: A

    Solution :

                    Fe is more electropositive than copper. Hence \[C{{u}^{2+}}\] can oxidise Fe.


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