A) 0.177 V
B) ? 0.177 V
C) 0.087 V
D) 0.059 V
Correct Answer: B
Solution :
Reduction potential of hydrogen electrode, \[{{E}_{H}}=\frac{-2.303\,\text{RT}}{F}\,\,\log \frac{1}{[{{H}^{+}}]}\] \[=-0.059\,pH=-0.059\times 3=-0.177\,V\].You need to login to perform this action.
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