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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Electrode potential Ecell Nernst equation and ECS

  • question_answer
    The standard electrode potential of the half cells are given below \[Z{{n}^{2+}}+2{{e}^{-}}\to Zn;E=-7.62\,\,V,\]\[F{{e}^{2+}}+2{{e}^{-}}\to Fe;E=-7.81\,\,V\] The emf of the cell \[F{{e}^{2+}}+Zn\to Z{{n}^{2+}}+Fe\] is [CPMT 2003]

    A)                 1.54 V   

    B)                 ? 1.54 V

    C)                 ? 0.19 V               

    D)                 + 0.19 V

    Correct Answer: C

    Solution :

               \[F{{e}^{2+}}+Zn\to Z{{n}^{2+}}+Fe\]            \[EMF={{E}_{\text{cathode}}}-{{E}_{\text{anode}}}\]\[{{H}^{+}}(0.025\,M)\to {{H}^{+}}({{10}^{-8}}\,M)\]                                 \[EMF=-0.19\,V\].          


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