A) \[\frac{RT}{f}\log \frac{{{P}_{1}}}{{{P}_{2}}}\]
B) \[\frac{RT}{2f}\log \frac{{{P}_{1}}}{{{P}_{2}}}\]
C) \[\frac{RT}{f}\log \frac{{{P}_{2}}}{{{P}_{1}}}\]
D) None of these
Correct Answer: B
Solution :
Anodic reaction : \[{{H}_{2}}({{P}_{1}})\to 2{{H}^{+}}\] Cathodic reaction : \[2{{H}^{+}}\to {{H}_{2}}({{P}_{2}})\] \[{{E}_{cathode}}=-\frac{RT}{2F}\ln \frac{{{P}_{2}}}{{{[{{H}^{+}}]}^{2}}}\] ; \[{{E}_{\text{anode}}}=-\frac{RT}{2F}\ln \frac{{{[{{H}^{+}}]}^{2}}}{{{P}_{1}}}\] \[{{E}_{\inf }}={{E}_{anode}}+{{E}_{cathode}}\] \[=-\frac{RT}{2F}\ln \frac{{{({{H}^{+}})}^{2}}}{{{P}_{1}}}-\frac{RT}{2F}\ln \frac{{{P}_{2}}}{{{({{H}^{+}})}^{2}}}\] \[=-\frac{RT}{2F}\ln \frac{{{P}_{2}}}{{{P}_{1}}}=\frac{RT}{2F}\ln \frac{{{P}_{1}}}{{{P}_{2}}}\].
You need to login to perform this action.
You will be redirected in
3 sec
