A) \[Fe\]
B) Mn
C) Cr
D) Co
Correct Answer: C
Solution :
Reduction \[{{E}_{0}}{{M}^{3+}}/{{M}^{2+}}\] | Cell reaction | \[{{E}_{0}}{{M}^{2+}}/{{M}^{3+}}\](Oxidation) | |
? .41 V | \[C{{r}^{2+}}\] | \[C{{r}^{3+}}\] | + . 41 V |
+ 1.57 V | \[M{{n}^{2+}}\] | \[M{{n}^{3+}}\] | ? 1.57 V |
+ 0.77 V | \[F{{e}^{2+}}\] | \[F{{e}^{3+}}\] | ? 0.77 V |
+ 1.97 V | \[C{{o}^{2+}}\] | \[C{{o}^{3+}}\] | ? 1.97 V |
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