A) Copper chloride in water
B) \[NaCl\] in water
C) \[{{H}_{2}}S{{O}_{4}}\]
D) Water
Correct Answer: B
Solution :
Since discharge potential of water is greater than that of sodium so water is reduced at cathode instead of \[N{{a}^{+}}\] Cathode: \[{{H}_{2}}O+{{e}^{-}}\to \frac{1}{2}{{H}_{2}}+O{{H}^{-}}\] Anode: \[C{{l}^{-}}\to \frac{1}{2}C{{l}_{2}}+{{e}^{-}}\].You need to login to perform this action.
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