A) \[{{H}_{2}},\,\,\,{{O}_{2}}\]
B) \[{{O}_{2}},\,\,{{H}_{2}}\]
C) \[{{O}_{2}},\,\,Na\]
D) \[{{O}_{2}},\,\,S{{O}_{2}}\]
Correct Answer: A
Solution :
At cathode: \[2{{H}^{+}}+2e\to {{H}_{2}}\], At anode : \[2O{{H}^{-}}\to {{H}_{2}}O+\frac{1}{2}{{O}_{2}}+2e\]
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