A) \[{{H}_{2}}\] gas at the anode
B) \[{{H}_{2}}\] gas at the cathode
C) \[C{{l}_{2}}\] gas at the cathode
D) \[C{{l}_{2}}\] and \[{{O}_{2}}\] gases both at the anode
Correct Answer: B
Solution :
\[2{{H}^{+}}+2{{e}^{-}}\to {{H}_{2(g)}}\] at cathode.
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