A) \[{{O}_{2}}\] and \[{{H}_{2}}\]
B) \[S{{O}_{2}}\] and \[{{H}_{2}}\]
C) \[{{H}_{2}}\] and \[{{O}_{2}}\]
D) \[S{{O}_{3}}\] and \[{{O}_{2}}\]
Correct Answer: A
Solution :
Cathode: \[2{{H}_{2}}O+2{{e}^{-}}\to {{H}_{2}}+2O{{H}^{-}}\] Anode : \[{{H}_{2}}O\to 2{{H}^{+}}+\frac{1}{2}{{O}_{2}}+2{{e}^{-}}\].
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