SSC Quantitative Aptitude Algebra Question Bank Elementary Algebra (I)

  • question_answer
    Let \[x=\frac{\sqrt{13}+\sqrt{11}}{\sqrt{13}-\sqrt{11}}\]and \[y=\frac{1}{x},\]then the value of\[3{{x}^{2}}-5xy+5{{y}^{2}}\]is [SSC CGL Tier II, 2015]

    A) 1771

    B) 1177

    C) 1717

    D) 1171

    Correct Answer: C

    Solution :

    [c] \[x=\frac{\sqrt{13}+\sqrt{11}}{\sqrt{13}-\sqrt{11}}=\frac{{{(\sqrt{13}+\sqrt{11})}^{2}}}{{{(\sqrt{13})}^{2}}-{{(\sqrt{11})}^{2}}}\] \[=\frac{13+11+2\sqrt{13}\sqrt{11}}{13-11}=\frac{24+2\sqrt{143}}{2}=12+\sqrt{143}\] \[y=\frac{1}{x}=\frac{1}{12+\sqrt{143}}=\frac{12-\sqrt{143}}{{{(12)}^{2}}-{{(\sqrt{143})}^{2}}}=\frac{12-\sqrt{143}}{144-143}=12-\sqrt{143}\] \[\therefore \]      \[3{{x}^{2}}-5xy+3{{y}^{2}}=3\,{{(12+\sqrt{143})}^{2}}-5\,(12+\sqrt{143})\] \[(12-\sqrt{143})+3\,{{(12-\sqrt{143})}^{2}}\] \[=3\,(144+143+24\sqrt{3})-5\,(144-143)+\,3\,(144+143-24\sqrt{3})\]\[=3\times 287+3\times 24\sqrt{3}-5+3\times 287-3\times 24\sqrt{3}\] \[=1722-5=1717\]


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