SSC Quantitative Aptitude Algebra Question Bank Elementary Algebra (I)

  • question_answer
    If \[\sqrt{x}=\sqrt{3}-\sqrt{5},\]then the value of \[{{x}^{2}}-16x+6\]is

    A) 0

    B) \[-\,2\]

    C) 2

    D) 4

    Correct Answer: C

    Solution :

    [c] \[\sqrt{x}=\sqrt{3}-\sqrt{5}\]\[\Rightarrow \]\[{{(\sqrt{x})}^{2}}={{(\sqrt{3}-\sqrt{5})}^{2}}\] \[\Rightarrow \]   \[x=3+5-2\sqrt{15}\] \[\Rightarrow \]   \[x-8=-\,2\sqrt{15}\] \[\Rightarrow \]   \[{{(x-8)}^{2}}={{(-2\sqrt{15})}^{2}}\] \[\Rightarrow \]   \[{{x}^{2}}+64-16=60\] \[\Rightarrow \]   \[{{x}^{2}}-16x+4=0\]\[\Rightarrow \]\[{{x}^{2}}-16x+6=2\]


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