A) 0
B) 667
C) 1000
D) 2334
Correct Answer: C
Solution :
[c] \[{{x}^{3}}+{{y}^{3}}+{{z}^{3}}3xyz=\frac{1}{2}(x+y+z)\] \[[{{(x-y)}^{2}}+{{(y-z)}^{2}}+{{(z-x)}^{2}}]\] \[=\frac{1}{2}(333+333+334)\] \[[{{(0)}^{2}}+{{(-1)}^{2}}+{{(1)}^{2}}]=1000\] |
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