SSC Quantitative Aptitude Algebra Question Bank Elementary Algebra (I)

  • question_answer
    If \[a=11\]and \[b=9,\]then the value of \[\left( \frac{{{a}^{2}}+{{b}^{2}}+ab}{{{a}^{3}}-{{b}^{3}}} \right)\]is

    A) \[\frac{1}{2}\]

    B) \[2\]

    C) \[\frac{1}{20}\]

    D) \[20\]

    Correct Answer: A

    Solution :

    [a] If \[a=11\]then \[b=9,\] \[\frac{{{a}^{2}}+{{b}^{2}}+ab}{{{a}^{3}}-{{b}^{3}}}=\frac{{{a}^{2}}+{{b}^{2}}+ab}{(a-b)({{a}^{2}}+{{b}^{2}}+ab)}\] \[=\frac{1}{(a-b)}=\frac{1}{11-9}=\frac{1}{2}\]


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