SSC Quantitative Aptitude Algebra Question Bank Elementary Algebra (II)

  • question_answer
    Is \[{{2}^{32}}-(2+1)({{2}^{2}}+1)({{2}^{4}}+1)({{2}^{8}}+1)({{2}^{16}}+1)\]equal to

    A) \[0\]

    B) \[1\]

    C) \[2\]

    D) \[{{2}^{16}}\]

    Correct Answer: B

    Solution :

    [b] \[{{2}^{32}}-(2+1)({{2}^{2}}+1)({{2}^{4}}+1)({{2}^{8}}+1)({{2}^{16}}+1)\] \[={{2}^{32}}-(2-1)(2+1)({{2}^{2}}+1)({{2}^{4}}+1)({{2}^{8}}+1)({{2}^{16}}+1)\]      \[={{2}^{32}}-({{2}^{2}}-1)({{2}^{2}}+1)({{2}^{4}}+1)({{2}^{8}}+1)({{2}^{16}}+1)\] \[={{2}^{32}}-({{2}^{4}}-1)({{2}^{4}}+1)({{2}^{8}}+1)({{2}^{16}}+1)\] \[={{2}^{32}}-({{2}^{8}}-1)({{2}^{8}}+1)({{2}^{16}}+1)\] \[={{2}^{32}}-({{2}^{16}}-1)({{2}^{16}}+1)\] \[={{2}^{32}}-({{2}^{32}}-1)=1\]


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