A) \[3\,\,(y-z)(z+x)(y-x)\]
B) \[(x-y)(y+z)(x-z)\]
C) \[3\,(y-z)(z-x)(x-y)\]
D) \[(y-z)(z-x)(x-y)\]
Correct Answer: C
Solution :
[c] Suppose, \[y-z=a,\]\[z-x=b\]and \[x-y=c\] \[\therefore \] \[a+b+c=0\] \[\Rightarrow \] \[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}=3abc\] \[=3\,(y-z)(z-x)(x-y)\] |
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