A) \[1\]
B) \[-1\]
C) \[0\]
D) \[2\]
Correct Answer: A
Solution :
[a] \[{{(5a+4b)}^{2}}=25{{a}^{2}}+40ab+16{{b}^{2}}\] Given, \[a=23,\]\[b=-29\] \[\therefore \] \[{{(5a+4b)}^{2}}={{[5\times 23+4\,(-29)]}^{2}}\] \[={{(115-116)}^{2}}\] \[={{(-1)}^{2}}=1\] |
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