JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Elevation of boiling point of the solvent

  • question_answer
    The latent heat of vapourisation of water is \[9700\,Cal/mole\] and if the b.p. is \[{{100}^{o}}C\], ebullioscopic constant of water is [CBSE PMT 1989]

    A)                 \[{{0.513}^{o}}C\]           

    B)                 \[{{1.026}^{o}}C\]

    C)                 \[{{10.26}^{o}}C\]           

    D)                 \[{{1.832}^{o}}C\]

    Correct Answer: A

    Solution :

                \[{{K}_{b}}=\frac{{{M}_{1}}RT_{0}^{2}}{1000\,\,\Delta {{H}_{V}}}=\frac{18\times 1.987\times {{(373)}^{2}}}{1000\times 9700}\]\[={{0.513}^{o}}C\]


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