JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Elevation of boiling point of the solvent

  • question_answer
    The molal boiling point constant for water is \[{{0.513}^{o}}C\,kg\,mo{{l}^{-1}}\]. When 0.1 mole of sugar is dissolved in \[200ml\] of water, the solution boils under a pressure of one atmosphere at                                               [AIIMS 1991]

    A)                 \[{{100.513}^{o}}C\]      

    B)                 \[{{100.0513}^{o}}C\]

    C)                 \[{{100.256}^{o}}C\]      

    D)                 \[{{101.025}^{o}}C\]

    Correct Answer: C

    Solution :

             \[\Delta {{T}_{b}}={{K}_{b}}\times m=0.513\times \left( \frac{0.1}{200}\times 1000 \right)\]                                 \[=0.2565{{\,}^{o}}C\], \[{{T}_{b}}=100\,.\,{{256}^{o}}C\]


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