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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Elevation of boiling point of the solvent

  • question_answer
    When 10g of a non-volatile solute is dissolved in 100 g of benzene, it raises boiling point by \[{{1}^{o}}C\] then molecular mass of the solute is \[({{K}_{b}}\]for benzene =2.53k-m?1)            [BHU 2002]

    A)                 223 g     

    B)                 233 g

    C)                 243 g     

    D)                 253 g

    Correct Answer: D

    Solution :

             \[\Delta {{T}_{b}}=\frac{{{K}_{b}}\times w\times 1000}{m\times W}\]                 \[m=\frac{{{K}_{b}}\times w\times 1000}{\Delta {{T}_{b}}\times W}\]\[=\frac{2.53\times 10\times 1000}{1\times 100}=253g\].


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