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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Elevation of boiling point of the solvent

  • question_answer
    The molal elevation constant of water \[={{0.52}^{o}}C\]. The boiling point of 1.0 molal aqueous \[KCl\] solution (assuming complete dissociation of \[KCl\]), therefore, should be     [BHU 1987]

    A)                 \[{{100.52}^{o}}C\]         

    B)                 \[{{101.04}^{o}}C\]

    C)                 \[{{99.48}^{o}}C\]           

    D)                 \[{{98.96}^{o}}C\]

    Correct Answer: B

    Solution :

             \[\Delta {{T}_{b}}=im{{k}_{b}}=0.52\times 1\times 2=1.04\].                 \ \[{{T}_{b}}=100+1.04={{101.04}^{o}}C\].


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