A) \[{{t}_{1}}={{t}_{2}}\]
B) \[{{t}_{1}}>{{t}_{2}}\]
C) \[{{t}_{2}}>{{t}_{1}}\]
D) \[{{t}_{2}}\] is approximately equal to \[{{t}_{1}}\]
Correct Answer: B
Solution :
\[BaC{{l}_{2}}\] furnishes more ions than \[KCl\] and thus shows higher boiling point \[{{T}_{1}}>{{T}_{2}}\].
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