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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Elevation of boiling point of the solvent

  • question_answer
    If \[0.15\,g\] of a solute dissolved in \[15\,g\] of solvent is boiled at a temperature higher by \[{{0.216}^{o}}C\] than that of the pure solvent. The molecular weight of the substance  (molal elevation constant for the solvent is \[{{2.16}^{o}}C\]) is [CBSE PMT 1999; BHU 1997]

    A)                 1.01       

    B)                 10

    C)                 10.1       

    D)                 100

    Correct Answer: D

    Solution :

                \[m=\frac{{{K}_{b}}\times w\times 1000}{\Delta {{T}_{b}}\times W}=\frac{2.16\times 0.15\times 1000}{0.216\times 15}\]= 100 .


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